Question

calculate the no of oxygen atoms & its weight in 50 gm of caco3.

Answer 1

no.of atoms=mass ofatom/atomic mass ×NA
NA is avogadros number which is 6.02£23

Answer 2

$\huge\red{\boxed{\bold{Solutions}}}$

• No. Of moles of CaCO3 = 50/100 = 0.5. (mol. At of CaCO3 = 100)

$\large\underline\mathrm\orange{Now}$,

• 1 molecules of CaCO3 contain 3 atom of O.

$\large\underline\mathrm\orange{Or}$

• 1 mole of CaCO3 contain 3 atom of O.

$\large\underline\mathrm\orange{Or}$

• 0.5 mole of CaCO3 contain 1.5 atom of O.

.:. No. of atom of O = no. 1.5 × 6.022 × 10^23.

$\implies$ 9.033 × 10^23.

.:. Wt. Of atom of O = no. of moles × at. Wt. of O

$\implies$ 1.5 × 16

$\implies$ 24 g.

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