Question

Calculate the no. Of oxygen atoms and its weight in 50g of caco3

Answer 1

Answer:

1.5 atoms of oxygen

Explanation:

molar mass of CaCO3 = 40+12+16+16+16

=100

moles of CaCO3 =50/100

=0.5

1mole of CaCO3 have 3 oxygen atoms so 0.5 moles of CaCO3 will have 1.5 atoms of oxygen

Answer 2

$\huge\red{\boxed{\bold{Solutions}}}$

• No. Of moles of CaCO3 = 50/100 = 0.5. (mol. At of CaCO3 = 100)

$\large\underline\mathrm\orange{Now}$,

• 1 molecules of CaCO3 contain 3 atom of O.

$\large\underline\mathrm\orange{Or}$

• 1 mole of CaCO3 contain 3 atom of O.

$\large\underline\mathrm\orange{Or}$

• 0.5 mole of CaCO3 contain 1.5 atom of O.
• No. of atom of O = no. 1.5 × 6.022 × 10^23.

$\implies$ 9.033 × 10^23.

• Wt. Of atom of O = no. of moles × at. Wt. of O.

$\implies$ 1.5 × 16

$\implies$ 24 g.

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