calculate the no. of ozone molecules and that of oxygen atoms present in 64g of ozone.
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Mass of O3 = 16*3
= 48.
no. of moles = given mass/molar mass
so, moles of O3= 64/48
= 1.33 moles (approx.)
now, no of moles = no. of particles / avogadro's no.
no. of particles of ozone = 1.33 * 6.022*10^23
= 8.01 * 10^23 (approx.)
Now, o3 has three atoms of oxygen
so, no of moles (O) = 64/16
= 4
no. of particles = 4 * 6.022 * 10^23
= 24.088 * 10^23 or 2.4088 * 10^24 (im not sure about this one though, is this correct?)
= 48.
no. of moles = given mass/molar mass
so, moles of O3= 64/48
= 1.33 moles (approx.)
now, no of moles = no. of particles / avogadro's no.
no. of particles of ozone = 1.33 * 6.022*10^23
= 8.01 * 10^23 (approx.)
Now, o3 has three atoms of oxygen
so, no of moles (O) = 64/16
= 4
no. of particles = 4 * 6.022 * 10^23
= 24.088 * 10^23 or 2.4088 * 10^24 (im not sure about this one though, is this correct?)
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Answer:
it is right k I also got same
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