Question

Calculate the no. of particles in 14g of C2h6 (Ethan) ?​

Answer 1

Given Molecule: C2H6 [Ethane].

Constituents with their Molecular Mass:

1. C: 12 g/mol.

2. H: 1 g/mol.

Molecular Mass of Ethane:

= 2(12) + 6(1).

= 24 + 6.

= 30 g/mol.

Given Mass: 14g.

Number of moles of Ethane(n):

n = Given Mass/Molecular Mass.

n = 14g/30 g/mol.

n = 7/15.

n = 0.46 moles.

Number of Molecules = n * Avogadro's Number.

No. Of Molecules = 0.46 * 6.022*10^23.

No. Of Molecules = 2.77*10^23.

So, the given mass of compound has:

2.77 * 10^23 molecules of ethane.

2 * 2.77 * 10^23 atoms of Carbon.

6 * 2.77 * 10^23 atoms of Hydrogen.