Question

calculate the no. of particles in each of the following. (i) 46g of sodium atom. (ii) 8g of oxygen. (iii) 0.1 mole of oxygen​

Answer 1

Answer:

Explanation:

1st moles=46/23=2

no of particles-mole-Na

=2×6.02×10^23

=12.04×10^23

2nd moles= 8/32=1/4

no of particles=1/4x6.02x10^23

= 1.505x10^23

3rd moles= 0.1 (given)

no of particles= 0.1x6.02×10^23

= 0.602x10^23

Answer 2

Answer: (i) 1.2044 × 10²⁴ particles .

(ii) 3.011 × 10²³ particles .

(iii) 6.022 × 10²² particles .

Explanation :-

For number (i) :-

Molar mass of Sodium is 23 g/mol.

So required number of particles in 46 g of it will be :-

= Number of moles × Avogadro Number

= (46/23) × 6.022 × 10²³

= 2 × 6.022 × 10²³

= 12.044 × 10²³

= 1.2044 × 10²⁴

For number (ii) :-

Molar mass of Oxygen is 16 g/mol and given mass is 8 grams. Thus, no of particles :-

= (8/16) × 6.022 × 10²³

= 0.5 × 6.022 × 10²³

= 3.011 × 10²³

For number (iii) :-

Here we are given with 1 mole of Oxygen . So we will put values again and obtain it as :-

= 0.1 × 6.022 × 10²³

= 0.6022 × 10²³

= 6.022 × 10²²