Question

Calculate the no. of particles present in 51g of Al2O3​

Answer 1

Answer:

1 mole of Aluminium Oxide (Al2O3) = 2 × 27 + 3 × 16 = 102 g. ...

We know, The number of atoms present in given mass = (Given mass ÷ molar mass) × Avogadro number.

Then, 0.051 g of Aluminium Oxide (Al2O3) contains.

= (0.051 ÷ 102 ) × 6.022 × 1023 molecules of Aluminium Oxide (Al2O3)

Explanation:

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Answer 2

Answer:

molar mass of al₂o₃ = 26 × 2 +  + 16 × 3 = 52+48 = 100

then,

given mass/molar mass =no. of moles

51/100 = 0.51 moles

no. of particles / Avogadro number(6.022 × 10²³) = no. of moles

no. of particles =  no. of moles × Avogadro number(6.022 × 10²³)

no. of particles = 0.51 × 6.022 × 10²³ = 3.07122 × 10²³