Question

calculate the no. of protons in 10g of CaCO3 . NA=6.02* 1023.

Answer 1

molecular mass of CaCO3 =
40+12+16*3=40+12+48
=100gm
no.of protons in one molecule of
CaCO =20+6+8*3
=50
no of protons in one mole of CaCO i.e.
100gm of CaCO =6.02*10 *no. of
protons in one molecule
=6.02*10 *50
=301*10
so now,
no. of protons in 10gm of
CaCO =301*10 /10
=301*10
hence no. of protons in 10 gm of
CaCO will be 301*10 protons
3.011*10
Hii Easy solutions Go for it guys
Hi easy answer go for it guys
See this
10 gram of calcium carbonate contains