Question

Calculate the no. of protons in 30g of CO3 ion

Answer 1

in 30 g of calcium carbonate, there will be

30g / 100g-mol = 0.3 mol

One mole of molecules is defined by

6.02 x 10^23 molecules.

Therefore, there exist

6.02 × 10^23 × 0. 3

= 1.80 × 10^23 molecules of calcium carbonate.

caco3 consists of one calcium atom, one carbon atom, and three oxygen atoms.

A calcium atom has 20 protons, a carbon atom has 6 protons, and one oxygen atom has 8 protons, and so three oxygen atoms would have 8×3=24 protons.

In total, one molecule of calcium carbonate has

20+6+24=50

protons. But, we have

1.80 × 10^23 molecules of calcium carbonate.

Therefore, in total, we would have

1.80 × 10^23 × 50

=9.03 × 10^24 protons