Question

calculate the no. of protons present in 10g of CaCO3​

Answer 1

Hey there!

1 mole of Caco3 weighs 100g.

So, 100g of Caco3 contains 6 * 10^23 molecules.

But, We are looking for 10g.

So 100 -> 6 * 10^23

10 -> x

x = 6 * 10^22 molecules.

We know that,

Number of protons in a molecule is directly its atomic number.

So, Ca- 18

C - 6

O - 8 * 3 = 24

Totally, 50 protons and 50 electrons in one molecule of CaCO3

And now,

Number of protons in 10g

= Number of protons in 6 * 10^22 molecules.

= 50 * 6 * 10^22

= 3 * 10^2 * 10^22

= 3 * 10^24 protons.

Therefore, There are 3 * 10^24 protons.

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