Calculate the no. of sides of a regular polygon if its exterior angle exceeds its interior angle by 60 degree.
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let the interior angle be x
thus , exterior angle = x+60
x+x+60=180. ...adjacent angles
x=60
exterior angle =120°
as we know that sum of all the exterior angles of any polygon is 360
so ,360÷120=3
no of sides =3
thus , exterior angle = x+60
x+x+60=180. ...adjacent angles
x=60
exterior angle =120°
as we know that sum of all the exterior angles of any polygon is 360
so ,360÷120=3
no of sides =3
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