Question

Calculate the no. of sulphur atoms in one mole of 5 grams​

Answer 1

$\huge\underline\purple{\sf Answer:-}$

★$\large{\boxed{\sf No.\:of\:S\:Atoms=9×{10}^{22}Atoms}}$

$\huge\underline\purple{\sf Solution:-}$

Given :-

Mass of Sulphur ( S) = 5 g

And

We know that

$\large{\sf 1\:mole=6.022×{10}^{23}}$

Here

We have 5 g of sulphur so,

★$\large{\boxed{\sf Mole(n)={\frac{Mass}{Molecular\:Mass}}}}$

We know that

Molecular weight of sulphur is 32

$\large\implies{\sf {\frac{5}{32}}}$

$\large\implies{\sf 0.15\:moles}$

Since ,

$\large{\sf 1\:mole=6.022×{10}^{23}Atoms}$

therefore

$\large{\sf 0.15\:moles=0.15×6.022×{10}^{23}}$

$\large\implies{\sf 0.9×{10}^{23}}$

★$\large\red{\boxed{\sf No.of\:S\: Atoms=9×{10}^{22}Atoms}}$