Question

calculate the no. of total atoms in 84 amu of nh3​

Answer 1

Answer 4

Explanation:

The number of molecules in 34 g $N{H_3}$ is shown below. In $N{H_3}$ molecule one nitrogen atom and three hydrogen atoms are present. So in 1 mol of $N{H_3}$ molecule, the total number of atoms present is 4.

Answer 2

Explanation:

$\frac{given \: mass}{molar \: mass} = \frac{number \: of \: atoms \: in \:NH_3 }{avogadros \: number} \\ \\ \frac{1.67 \times {10}^{ - 27} }{84} = \frac{number \: of \: atoms \: in \:NH_3 }{6.022 \times {10}^{23} } \\ \\ Number \: of \: atoms \: in \:NH_3 \\ = \frac{1.67 \times {10}^{ - 27} \times 6.022 \times {10}^{23} }{84} \\ = \frac{ {10}^{ - 3} }{84} \\ = 0.0119 \times {10}^{ - 3} \\ = 1.19 \times {10}^{ - 5} \: atom \\ \\ \red{\mathfrak{ \large{\underline{{Hope \: It \: Helps \: You}}}}} \\ \blue{\mathfrak{ \large{\underline{{Mark \: Me \: Brainliest}}}}}$