Calculate the no. of unpaired electrons
in Si(z=14) and fe(z=26)
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Answer:
p with atomic number 15 with electronic configuration [Ne]3s23p3 contains 3 unpaired electrons.
(b) Si with atomic number 16 with electronic configuration [Ne]3s23p2 contains 2 unpaired electrons.
(c) Cr with atomic number 24with electronic configuration [Ar]3d54s1 contains 6 unpaired electrons.
(d) Fe with atomic number 26 with electronic configuration [Ar]3d64s2 contains 4 unpaired electrons.
(e) Kr with atomic number36 [Ar]3d104s24p6 contains 0 unpaired electrons.
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