Question

Calculate the no. Of water molecules present in 5 ml of water

Answer 1

Hi mate.

Thanks for asking this question.

Here is your answer,



Given,

V = 2 ml

= 0.002 L



We know that,

n = v / 22.4

n = 0.002 / 22.4


$n \: = 2 \times {10}^{ - 3} \div 22.4$

$n \: = \: 0.089 \times {10}^{ - 3}$
For the no of molecules,

We have a not a formula but we have a concept,


We know that,


$avagdro \: no. \: = \: 6.022 \times {10}^{23}$

Therefore,

No of molecules = n ×avagdro number


$no \: of \: molecule \: = 0.089 \: \times {10}^{ - 3} \times \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 6.022 \times { {10}^{} }^{23}$

$no \: of \: molecule \: = 0.537 \times {10}^{20}$




Thank you.



BE BRAINLY !!!!!!!!!!!!!