Question

Calculate the noramtily of 0.63 gram of oxalic acid in 100 ml of solution

Answer 1

Answer:

0.1 N

Explanation:

                                Oxalic acid ( C₂H₂O₄ .2H₂O )

Moles = 0.63 / 126 = 0.005

n-factor =  2 (because oxalic acid has 2 free H+ ions to donate )

Volume = 100 ml / 1000 = 0.1 liter

Normality = equivalence / volume

                   = 0.005 x 2 / 0.1

                   =0.1 N

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