Question

calculate the normality and molarity of 5% of NaOH​

Answer 1

As, density of solution is not given, moreover it has not been mentioned whether the 5 % NaOH solution is W/W or W/V therefore we have considered it as W/V. Hence, 5 % NaOH means 5g of NaOH present in 100 mL of solution. Therefore its acidity is 1.

Answer 2

Answer:

Explanation:

5% solution means 5 grams of NaOH is present in 100 ml of solution weight of solute = 5gms volume of solute =100 'Il molarity weight of solute/G.M.W ×1000/100 N=5/40x1000/100 =1.25N

M=5/40×1000/100

= 1.25M

normality=w/G.E.W X1/V