Chemistry, asked by pialouiseeee, 5 hours ago

Calculate the normality and molarity of a solution containing 26.8 g of sodium carbonate, Na2CO3 per liter of solution

Answers

Answered by lks187

3

Answer:

Given-

Weight of solute = 26.8g

volume = 1 litre

moles of solute = weight of solute ÷ molar mass

= 26.8 ÷ 106

= 13.4 / 53

Molarity = (13.4/53)÷ 1 liter

= 0.25 mol/litre

Normality = no. of gram equivalent of substance/ Volume of solution

equivalent of substance = given mass / equivalent

weight

= 26.8/106

=13.4/53

N = 13.4/53÷1 liter

= 0.25 N

Hope this helps you

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