Question

calculate the normality and molarity of h2so4 solution containing 4.9g of h2so4 per litre of the solutuon.

Answer 1

Answer: Molarity of sulfuric acid solution is 0.0499 mol/L.

Normality of sulfuric acid solution is 0.0998 gram equivalent per liters.

Explanation:

Molarity = $\frac{\text{Mass of compound}}{\text{molar mass of compound}\times \text{volume of solution is liters}}$

Molarity of sulfuric acid solution:

$M=\frac{4.9 g}{98.07 g/mol\times 1L}=0.0499 mol/L$

Molarity of sulfuric acid solution is 0.0499 mol/L.

Normality = $n\times \frac{\text{Mass of compound}}{\text{molar mass of compound}\times \text{volume of solution is liters}}$

n =number of Ionizable Hydrogen ions for an acid or number of ionizable hydroxide ions for base.

Normality of sulfuric acid :

$M=2\times \frac{4.9 g}{98.07 g/mol\times 1L}=0.0998$ gram equivalent per liters

Normality of sulfuric acid solution is 0.0998 gram equivalent per liters.

Answer 2

Answer:

0.05 M

Explanation:

formula:M=weight/mol.wt*1/v(in litres)

weight:4.9g

mol.wt:H2so4:98

volume:1 liter

4.9/98*1/1

point canel

49/980*1/1

1 and 1 cancel and 49 and 980 canel

=1/20=0.05M

step-step explanation