Question

Calculate the Normality of 0.05M H2SO4 solution?
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Answer 1

Answer:

0.025

Explanation:

as the hydrogen displace -2 the 2 is considered at equivalent mass the molarity * volume/equivalent mass = 0.05*1/2=0.025

Answer 2

ANSWER :-

We have to calculate Normality of 0.05M H2SO4 solution -

Given,

Molarity = 0.05 M

We will solve the problem by using this formula -

$Normality = Molarity \: × \: Acidity \: or \: Basicity \: ( Valency \: factor) \: \\ \\ number \: of \: replaceable \: {H}^{ + } ions \: is \: 2 \: be \: here \: </p><p>H2SO4 \: is \: di \: basic \: </p><p> \\ \\ \: Now \: \\ \: Normality \: = 0.05 \times 2 \: \\ = > Normality = 0.10 \\ i.e \: \\ 0.1N$

Hence, Normality of 0.05M H2SO4 solution is 0.1 N

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Definition of Normality -

It is defined as the number of Gram equivalent of solute per litre of solution. It is represented by "N"