Calculate the normality of 0.321 g sodium carbonate when it is mixed in a 250 mL solution
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Answer:
N=0.0755N
Explanation:
To solve this problem, you need to know the formula for sodium carbonate. Once you realize there are two sodium ions per carbonate ion, the problem is simple:
N=0.321gNa2CO3×(1mol/105.99g)×(2eq/1mol)
N=0.1886eq/0.2500L
N = 0.0755 N
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