calculate the normality of 0.321g of sodium carbonate which is mixed with 250ml of solutions
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Answered by
48
Answer:
Explanation:
To solve this problem, you need to know the formula for sodium carbonate. Once you realize there are two sodium ions per carbonate ion, the problem is simple:
N=0.321gNa2CO3×(1mol/105.99g)×(2eq/1mol)
N=0.1886eq/0.2500L
N = 0.0755 N
Answered by
1
The normality of the solution is 0.024N
GIVEN
Weight of Sodium Carbonate = 0.321 grams
Volume of solution = 250 ml
TO FIND
Normality of the Na₂CO₃
SOLUTION
We can simply solve the above problem as follows;
We know that,
Normality = Number of gram equivalent/Volume of solution.
Gram equivalent of Na₂CO₃ = Molar mass/n-factor
= 106/2
= 53
Volume of solution = 250 ml = 0.25 l
Putting the above values in the Normality formula;
N = 53/0.25
= 0.024 N
Hence, The normality of the solution is 0.024N
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