Question

Calculate the normality of 1.11gm cacl2 when it is dissolve in 250 ml solution

Answer 1

Answer:

0.08 N

Explanation:

$n = \frac{given \: mass}{equvqlent \: mass \: \times volume \: in \: lt}$

$n = \frac{1.11 \times 1000 \times 2}{111 \times 250} \\ n = 0.08$

Answer 2

Answer:

Normality = no.of gram equivalents of solute /Volume of solution (in litre)

equivalent mass = Molecular mass / Valency factor

= 111/2 [Ca^+0---->Ca^2+ + 2e-] = 55.5

No of gram equivalents = 1.11/55.5

=> Normality = 1.11/55.5 / 250/1000 = 0.08 N .