Question

calculate the normality of 20gm NaOH for 100 ml solution​

Answer 1

Answer:

5N

Explanation:

Normality = (weight÷ equivalent weight) * (1000 ÷ vol in ml)

= (20÷(40÷1)) * (1000÷100) = 0.5 * 10 = 5N

Answer 2

calculate the normality of 20gm NaOH for 100 ml solution....

answer : 5N

explanation : weight of sodium hydroxide, NaOH = 20gm

molecular weight of NaOH = 40g/mol

so, no of moles of NaOH = 20/40 = 0.5 mol

as, NaOH dissociates into Na+ and OH-

NaOH (aq) ⇔Na^+(aq) + OH^- (aq)

hence, n - factor of NaOH = 1

now, normality = n- factor × molarity

= n - factor × no of moles of NaOH/volume of solution in L

= 1 × 0.5/(100/1000)

= 5 N

hence, normality of the solution is 5N