Question

Calculate the normality of 4.9 g per liter H2SO4 solution.
Please write the whole method for better understanding. Thank you

Answer 1

$normlity = molarity \times valency \: factor \\ \: valency \: factor \: fo \: sulphuric \: acid = 2 \\ molarity = \frac{no \: of \: moles}{volume \: f \: soution} \\ = \frac{ \frac{4.9}{98} }{1} = 0.05M \\ normality = 0.05 \times 2 \\ = 0.1N$