Question

Calculate the normality of 9.8g h2so4 in 250 my solution

Answer 1

Answer i think the question is incomplete

Answer 2

SoluTion :-

$\sf {Moles\ of\ solute = \frac{Mass\ of\ solute }{Molar\ mass\ of\ solute}}\\\\\sf {\Rightarrow \frac{9.8 g}{98 g/mol} }\\\\\sf {\Rightarrow 0.1 mol}\\\\\\\sf {Volume\ of\ solution = 25 cm^3 = 0.025\ Litres}\\\\\\\sf {Molarity=\frac{Moles\ of\ solutes}{Volume\ of\ solution\ in\ litres} }\\\\\sf {\Rightarrow \frac{0.1 mol}{0.025\ Litres} }\\\\\sf {\Rightarrow 4\ M}$