Question

Calculate the normality of a 500 ml
of
solution containing 60gm of
NaOH in 2 litre
water is added to same
solution later find new
dilution.
normality after
dilution..?​

Answer 1

Answer:

Here, Let M

1

(molarity H

2

SO

4

)=2M, V

1

(volume of H

2

SO

4

)=20ml=0.02L, V

2

(volume of solution)=1L and M

2

(molarity of resulting solution)=?

Therefore, M

1

×V

1

=M

2

×V

2

M

2

=0.04M

Normality=M

2

×n , here n is number of H

+

ions an acid can donate

Normality=0.04×2=0.08N

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