Chemistry, asked by iamakashavodh, 16 days ago

calculate the normality of a solution containing 31.5g of hydrated oxalic acid in 1250ml of solution

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Answered by rekhabose84

1

Answer:

Normality = Number of g. ... Number of g. equivalents = 31.5/63 = 1/2 . Normality = 1/ 2 ⨯1250⨯ 1000 = 0.4 N.

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Answered by chnaidu1969

0

Explanation:

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