Question

Calculate the normality of a solution containing 5g of naoh in 450ml of solution

Answer 1

Solution:

We know that

N = n/V(lit)

Where

• N : Normality
• n : No. of moles
• V(lit) : Volume in litres

Firstly finding the no. of moles of NaOH

We know that

No. of moles = given mass/actual mass

No. of moles of NaOH = 5/40

No. of moles of NaOH = 0.125

★ Conversion:

450ml → L

1000ml = 1L

450ml = ? L

Let ? be x

By cross multiplying

1000 x = 450×1

x = 450/1000

450ml = 0.45L

Now , substituting the known values in N = n/V

♦ N = 0.125/0.45

♦ N = 0.2777

Hence , normality of the solution = 0.27 mol/L

Answer 2

The normality of a solution is 0.27N.

Given,

Amount of NaOH = 5 grams.

Amount of solutions = 450 ml.

To Find,

Normality of the solution.

Solution,

We can solve this type in the following manner.

Now,

N = n/V(lit)

here,

N = Normality

n = no of mole

V(lit) = volume in litres.

The molar mass of NaOH = 40g per mole.

Present moles in 5g of NaOH = 5/40 = 0.125.

The volume of solution = 450ml.

The normality of the solution = 0.125/450 = 0.00027× 1000 = 0.27

Hence, the normality of a solution is 0.27N.