Question

calculate the normality of a solution containing 6.3g oxalic acid dissolved in 250ml of solution​

Answer 1

Explanation:

this is the answer of question

Answer 2

Answer:

Explanation:

Normality of hydrated oxalic acid,N=W of oxalic acid/equivalent wt.×1000/v(ml).........(1)

oxalic acid equivalent mass

=Molecular mass/basicity=126/2=63 g/equiv..(2)

we put (2) on (1).

so we get,

Normality=6.3/63×1000/500

=0.1×2

=0.2 gmol/litre

Normality of hyadrated oxalic acid is 0.2 gram moles per litre.

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