Question

calculate the normality of a solution that contains 4.5 gram of (COOH) 2 in 3000ml of solution​

Answer 1

Answer:

Normality= 0.0334 N

Explanation:

To find the normality, we first find the molarity of the acid.

M = n/V (L)

n= m/molar mass

 = 4.5/90

n=0.05 mole

V= 3000ml = 3L

M= 0.05/3

M= =0.0167 M

Normality = molarity x n-factor

n factor = 2

Normality = 0.0167 *2 = 0.0334 N