Calculate the normality of aqueous solution containing 31.5g of oxalic acid in 2.5 litres solutions. Mol.wt.of oxalic acid =126
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Normality = Number of g. ... Number of g. equivalents = 31.5/63 = 1/2 . Normality = 1/ 2 ⨯1250⨯ 1000 = 0.4 N.
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