Calculate the normality of kcl solution at 298k resistance is found to be 2000ohm. cell constant is 5.53m-1 equivalent conductance is 138.25ohm-1 gm eq-1
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Explanation:
K (specific conductance) =
R
1
(
A
1
)
A
l
=1.29×10
−2
×300=3.87
l/A= cell constant ( cell constant same in both)
In Nacl Sol
n
k=
380
1
(
A
l
)
k=
380
1
×3.87=
380
3.87
=0.0101 onm
−1
cm
2
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