Chemistry, asked by sudhasandy, 3 months ago

calculate the normality of oxalic acid containg 6.3grams solute in 250 grams solution

Answers

Answered by kundanconcepts800

0

Explanation:

normality= no.of mol of solute /wt.of solvent in Kg

=.[ 6.3/63/(250-6.3)]×1000 m

= 0.41m

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