Question

Calculate the normality of oxalic acid solution when 0.63 grams of it is dissolved in water in 100 ml standard flask?

Answer 1

Answer:

Final Answer : Molarity : 0.02M

Normality : 0.04N

Steps:

1) Oxalic Acid: C2H2O4.(2H2O )

Molar Mass : 126g

Given Mass of Oxalic acid /solute = 0.63g

no. of moles of solute = 0.63/126 = 0.5 *10^(-2)

Volume of solution, V = 250cm^3 = 0.25L

=> Molarity, M

= no. of moles of solute / Volume of solution

= \frac{0.5 \times {10}^{ - 2} }{0.25} = 2 \times {10}^{ - 2}=

0.25

0.5×10

−2

=2×10

−2

Hence,Molarity = 0.02M

2) Since, Basicity / Valency Factor of acid is 2 .(Two ionisable H)

=> Normality =Molarity * Valency Factor

= 0.02M * 2 = 0.04N.

3) For Molality, Data is insufficient.

As We can't get Weight of solvent in solution from required data.