Question

Calculate the normality of solution containing 1.25g of k2cr2o7 in 250cmcube of solution

Answer 1

Answer:

0.05 ans

valency factor =3

normality=molarity× valency factor

calculate molarity

it come apx. = 0.017

normality=.017*3= 0.05

Answer 2

Answer:

H

3

PO

4

dissociates into3H

+

andPO

4

³−

so,n−factor of H

3

PO

4

=3

mass of H

3

PO

4

=4.9g/mol

molar mass ofH

3

PO

4

=3×1+31+4×16=3+31+64=98g/mol

so, no of moles of H

3

PO

4

=4.9/98=0.1/2=0.05mol

now , molarity=

volume of solution in Litre

no of moles of H

3

PO

4

=

0.5

0.05

=0.1M

weknow,

normality=n−factor×molarity

so,normality=3×0.1=0.3N