Question

Calculate the normality of solution containing 3.15 gram of hydrated oxalic acid

Answer 1

Answer:

Given: Wt. of solute = 3.15g

Volume = 1L

Equivalent Wt. = 126/2 = 63

Therefore ,

Normality = 3.12/1*63

Normality = 0.049 N,,

Hope it helps !!!

plz! Mark me as brainliest**

and don't forget to follow me ...✌✌