Calculate the normality of solution containing 6.3 g of hydrated oxalic acid in 500 ml of solution
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Molality of oxalic acid :
M×250×126=6.3×100
M=0.2
And normality would become
=0.2×2=0.4
M×250×126=6.3×100
M=0.2
And normality would become
=0.2×2=0.4
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