calculate the normality of the solution of HCl acid having 0.39gram are dissolve in 100 cm-3 of solution
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Answer:
no of moles= 0.39/36.5
=0.01
Explanation:
molarity = moles/volume
=0.01/10^-4
= 10^2
normality=molaity*Z
=10^2*1
=10^2 N
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