Calculate the number molecules present in 1.12cc of a gas at stp
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1.12cc=0.00112 liters
moles of gas = volume in liters ÷ volume at stp
moles of gas =0.00112÷22.4
moles of gas = 0.00005
NOW MOLES = NUMBER OF MOLECULES ÷ AVAGADRO NUMBER
NUMBER OF MOLECULES = MOLES × AVAGADRO NUMBER
NUMBER OF MOLECULES = 0.00005×6.023×10^23
NUMBER OF MOLECULES =0.00030115 ×10^23 = 3.0115×10^19
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1.12cc=0.00112 liters
moles of gas = volume in liters ÷ volume at stp
moles of gas =0.00112÷22.4
moles of gas = 0.00005
NOW MOLES = NUMBER OF MOLECULES ÷ AVAGADRO NUMBER
NUMBER OF MOLECULES = MOLES × AVAGADRO NUMBER
NUMBER OF MOLECULES = 0.00005×6.023×10^23
NUMBER OF MOLECULES =0.00030115 ×10^23 = 3.0115×10^19
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♡♤♡INSHALLAH IT WILL HELP U ♡♤♡
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HAVE A NICE DAY☺☺☺
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