Question

calculate the number of 1g He gas at NTP

Answer 1

howdy , your answer is ---

we know that atomic number of helium is 2 .

so , atomic mass of helium is 4amu .

now, 1 mole of helium = 4 gram ..(1)

also ,1 mole of helium = 6.002×10^23 atom. ....(2)

from (1) and (2)

6.002×10^23 = 4 gram

or , 1 gram = 6.002×10^23/4

=> 1 gram = 1.5 × 10^23 particle

now , at NTP

1 mole of helium = 22.4 L

so, 4 gram = 22.4 L

=> 1 gram = 22.4/4 L

=> 1 gram = 5.6 L

hence , 1 gram of helium gas = 1.5×10^23 particles and

1 gram of helium gas = 5.6 L Volume

Answer 2

Answer:

• 1 gram of Helium = 1.5055×10²³ particle
• Volume of 1 gram of helium = 5.6 L ( using NTP )

Explanation:

To find:

• The number of 1 g of He gas at NTP:

Solution:

Atomic number of Helium = 2

Molar mass of helium (1 mole) = 4.0026 g

                                    = 4 grams

1 mole of helium = 6.022×10²³ atoms

4 grams = 6.022×10²³ atoms

1 gram = $\frac{6.022*10^{23} }{4}$

1 gram of Helium = 1.5055×10²³ particle

At NTP:

To find volume of 1 gram of Helium:

The volume of 1 mole of Helium at NTP is 22.4 L

To calculate the volume of 1 g of helium:

4 gram of Helium = 22.4 L

Volume of 1 gram of helium = $\frac{22.4}{4}$

Volume of 1 gram of helium = 5.6 L

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