Question

calculate the number of Al3+ ions in 0.056 grams of Al2O3

Answer 1

Molar mass Al2O3 = 102 g / Mol 
Moles Al2O3 = 0.056 / 102 = 0.000549 
Moles Al3+ = 0.000549 x 2 = 0.00110 
Number of Al3+ ions = 0.00110 x 6.02 x10^23
=6.6 x 10^20

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