Question

Calculate the number of aloms and moleculs
in 3.6 g glucose
​

Answer 1

Answer:

C6H12O6 is the glucose molecule.

1 mole of glucose molecule is of:

(12*6)+(1*12)+(16*6) g

= 72+12+96 g

= 180 g

So, in just 3.6g of glucose, no. of moles is: 3.6/180

= 0.02

In 0.02 moles of glucose,

1. Atoms = (0.02*24)*6.022*10^24

= 0.48*6.022*10^24

= 2.89*10^24

2. Molecules = 0.02*6.022*10^24

= 0.120*10^24

or,

= 1.2*10^23

I hope this helps.