Chemistry, asked by debbarmajagatsen, 3 months ago

calculate the number of alpha and beta particles emitted by 92U²³⁸ to 82pb²⁰⁸.​

Answers

Answered by kritanuchatterjee280
0

Answer:

There are 8 α - emissions and 6 β - emissions

Explanation:

SORRY BRUH, BUT THERE IS A MISTAKE IN THE QUESTION, IT WOULD BE ₈₂Pb²⁰⁶

There is a transition from ₉₂U²³⁸ to ₈₂Pb²⁰⁶

Few things to be noticed -

1. There is a change in the mass number

2. There is a change in the atomic number

Things to keep in mind -

1. When an alpha emission occurs, the mass number decreases by 4 and the atomic number decreases by 2.

2. When a beta emission occurs, the mass number remains same but the atomic number increases by 1.

Solution -

Change in mass number - 238 - 206 = 32

Since, mass of every alpha particle is 4,

Let the number of alpha particles be α

4 α = 32

α = 8

Since, 8 alpha particles are released, the atomic number changes to 92 -2X 8 = 92-16= 76.

But the atomic number is 82, which shows there are beta emissions.

Let number of β - emissions be β

82 - β = 76

β = 6.

ANS - There are 8 α - emissions and 6 β - emissions

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