Question

Calculate the number of Aluminium ion in 0.56 gm of Alumina (Al2O3) ​

Answer 1

Answer:

6.023 × 10^21 aluminium ions.

Explanation:

1 mole of aluminum oxide Al203 = 2× 27 + 3× 16 = 102 u = 102 gram

So,

102 gm Al2O3 has = 6.023 × 10^23 Al203 molecules

0.56 gm Al2O3 has 6.023 ×1023 × 0.56/ 102

= 3.01 × 10 ^ 21 Al2O3 molecules

1 molecule of Al203 gives = 2Al3+ ions

Hence 0.56 gm Al203 gives = 2×3.01 × 10^21 Al3+ ions

= 6.023 × 10^21 aluminium ions.