Chemistry, asked by rdeka9090, 1 year ago

calculate the number of Aluminium ions present in 0.051 grams of Aluminium oxide

Answers

Answered by rishikumarjp2k3
5

Molecular weight of Al2O3 = 102 g

102 g of Al2O3 contains 6.022X1023 molecules

0.051g of Al2O3 contain X number of molecules

X = 0.051 X 6.022X1023 /102 = 0.003 X 1020

X = 3 X 1020

1 molecule of Al2O3 contains – 2 Al+3ions

3 X 1020 molecules contains – 2 X 3 X 1020

= 6 X 1020 Al+3 ions

∴0.051 g of Al2O3 contains 6 X 1020 Al+3 ions



rdeka9090: next gurukul answer
rdeka9090: right
rishikumarjp2k3: yes bro
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