Calculate the number of aluminium ions present in 0.051 g of aluminium oxide(Al=27,O=16)
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Answer:
Explanation:
Molar mass =100( app.)
Hence no of mole =0.051/100
= 51 x 10^-5
No of ion= 2x 6.022 x 10^24 x 51 x 10^-5
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