Calculate the number of aluminium ions present in 0.051 g of aluminium oxide.
Answers
Hᴇʀᴇ's Yᴏᴜʀ Aɴsᴡᴇʀ:-
Tʜɪs Pʀᴏʙʟᴇᴍ Iɴᴠᴏʟᴠᴇs Aʟᴜᴍɪɴɪᴜᴍ Iᴏɴs. Pʟᴇᴀsᴇ Nᴏᴛᴇ Tʜᴀᴛ Tʜᴇ Mᴀss ᴏғ Aʟᴜᴍɪɴɪᴜᴍ Iᴏɴ ɪs Tʜᴇ Sᴀᴍᴇ ᴀs Tʜᴀᴛ ᴏғ ᴀɴ Aʟɪᴍɪɴɪᴜᴍ Aᴛᴏᴍ. Iɴ Oʀᴅᴇʀ ᴛᴏ Sᴏʟᴠᴇ Tɪs Pʀᴏʙʟᴇᴍ, Fɪʀsᴛ ᴏғ Aʟʟ ᴡᴇ Hᴀᴠᴇ ᴛᴏ Fɪɴᴅ Oᴜᴛ Tʜᴇ Mᴀss ᴏғ Aʟᴜᴍɪɴɪᴜᴍ Aᴛᴏᴍs ɪɴ 0.051g ᴏғ Aʟᴜᴍɪɴɪᴜᴍ Oxɪᴅᴇ ( Wʜɪᴄʜ Wɪʟʟ Gɪᴠᴇ ᴜs Tʜᴇ Mᴀss ᴏғ Aʟᴜᴍɪɪᴜᴍ Iᴏɴs ) Tʜɪs Cᴀɴ ʙᴇ Dᴏɴᴇ ᴀs Fᴏʟʟᴏᴡs:-
1 Mᴏʟᴇ ᴏғ Al203 = Fᴏʀᴍᴜʟᴀ Mᴀss ᴏғ AI203 ɪɴ Gʀᴀᴍs
⇏Mᴀss ᴏғ AI × 2 + Mᴀss ᴏғ O × 3
⇏27 × 2 + 16 × 3
⇏54 + 48
⇏102 Gʀᴀᴍs
Nᴏᴡ 1 Mᴏʟᴇ ᴏғ AI203 Cᴏɴᴛᴀɪɴs 2 Mᴏʟᴇs ᴏғ AI
Sᴏ, Mᴀss ᴏғ AI ɪɴ 1 Mᴏʟᴇ ᴏғ AI203 = Mᴀss ᴏғ AI × 2
⇏27 × 2
⇏54 Gʀᴀᴍs
Nᴏᴡ, 102g Aʟᴜᴍɪɴɪᴜᴍ Oxɪᴅᴇ Cᴏɴᴛᴀɪɴs = 54g Al
Sᴏ, 0.051g Aʟᴜᴍɪɴɪᴜᴍ Oxɪᴅᴇ Cᴏɴᴛᴀɪɴs = 54/102 × 0.051g AI
= 0.027g AI
Tʜᴇ Aᴛᴏᴍɪᴄ Mᴀss ᴏғ Aʟᴜᴍɪɴɪᴜᴍ ɪs Gɪᴠᴇɴ ᴛᴏ ʙᴇ 27 ᴜ. Tʜɪs Mᴇᴀɴs Tʜᴀᴛ 1 Mᴏʟᴇ ᴏғ Aʟᴜᴍɪɴɪᴜᴍ Aᴛᴏᴍs ( ᴏʀ Aʟᴜᴍɪɴɪᴜᴍ Aᴛᴏᴍs ) Hᴀs Mᴀss ᴏғ 27 Gʀᴀᴍs, Aɴᴅ ɪᴛ Cᴏɴᴛᴀɪɴs 6.022 × 10^23
Nᴏᴡ 27 Gʀᴀᴍ ᴏғ Aʟᴜᴍɪɴɪᴜᴍ Hᴀs Iᴏɴs = 6.022 × 10^23
Sᴏ, 0.027 Gʀᴀᴍ ᴏғ Aʟᴜᴍɪɴɪᴜᴍ Hᴀs Iᴏɴs = 6.022 × 10^23/27 × 0.027
= 6.022 × 10^20
Tʜᴜs, Tʜᴇ Aʟᴜᴍɪɴɪᴜᴍ Iᴏɴs ɪɴ 0.051 Gʀᴀᴍ ᴏғ Aʟᴜᴍɪɴɪᴜᴍ Oxɪᴅᴇ ɪs 6.022 × 10^20.
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