Question

Calculate the number of aluminium ions present in 0.051g of aluminium oxide(atomic mass of al=27,0=16)

Answer 1

➡No of ions = mole x 6.022 x 10^23 x ions (from molecular formula)

Here ,

✔Aluminium oxide = Al2O3

✔Ions (from formula) = 2

No of moles = mass / molecular mass

Moles = 0.051/ 102

✔Moles = 1/ 2000

➡Putting in formula :

No of ions= 1/2000 x 6.022x 20^23x2

No of ions = 6.022 x 10^23 / 1000

✔No of ions = 6.022 x 10^20