calculate the number of aluminium ions present in 5.1g of aluminium oxide (atomic mass of al=27u o=16u)
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Hello! Let me try to answer this :)
NB:
Ar: Atomic mass
Mr: Molecular mass of Al2O3
= 27 x 2 + 16 x 3 = 102
Thanks and please correct if there are any mistakes ^ ^
NB:
Ar: Atomic mass
Mr: Molecular mass of Al2O3
= 27 x 2 + 16 x 3 = 102
Thanks and please correct if there are any mistakes ^ ^
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