Calculate the number of aluminum ions in 0.051 grams of aluminum oxide.
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molar mass =102 grams
102 g of aluminium oxide contains =2*6.022*10^23 al ions
0.051 contains =2*6.022*10^23*0.051/102
=6.022*10^20
102 g of aluminium oxide contains =2*6.022*10^23 al ions
0.051 contains =2*6.022*10^23*0.051/102
=6.022*10^20
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